A) Acetic acid
B) Bromoacetic acid
C) Methyl amine
D) Ethane
Correct Answer: C
Solution :
\[\underset{\text{Acetamide}}{\mathop{C{{H}_{3}}CON{{H}_{2}}}}\,+B{{r}_{2}}+4NaOH\to \]\[\underset{\text{Methyl amine}}{\mathop{C{{H}_{3}}N{{H}_{2}}}}\,+N{{a}_{2}}C{{O}_{3}}+2NaBr+2{{H}_{2}}O\]You need to login to perform this action.
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