A) 18
B) \[18\times 1000\]
C) \[{{N}_{A}}\]
D) \[55.55\,{{N}_{A}}\]
Correct Answer: D
Solution :
\[d=\frac{M}{V}\](d = density, M= mass, V =volume) Since d = 1 So, \[M=V\] 18gm = 18ml 18ml = NA molecules (NA = avogadro's no.) 1000ml \[=\frac{{{N}_{A}}}{18}\times 1000\] = 55.555 NA.
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