A) 20.8
B) 22.4
C) 2.24
D) 2.08
Correct Answer: B
Solution :
\[N{{a}_{2}}S{{O}_{4}}\ .\ 10{{H}_{2}}O\] \[=2\times 23+32+4\times 16+10\times 18\] \[=46+32+64+180=322gm\] 322gm \[N{{a}_{2}}S{{O}_{4}}.10{{H}_{2}}O\] contains = 224 gm oxygen 32.2gm \[N{{a}_{2}}S{{O}_{4}}.10{{H}_{2}}O\] contains = \[\frac{32.2\times 224}{322}=22.4\,gm\]You need to login to perform this action.
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