A) \[6.0\times {{10}^{23}}\]
B) \[3\times {{10}^{23}}\]
C) \[12\times {{10}^{23}}\]
D) \[3\times {{10}^{10}}\]
Correct Answer: A
Solution :
wt of \[C{{O}_{2}}=44\] mol wt of \[C{{O}_{2}}=44\] No. of molecule \[=\frac{\text{wt}\text{. of }C{{O}_{2}}}{mol\,wt\,of\,C{{O}_{2}}}\times 6.02\times {{10}^{23}}\] \[=\frac{44}{44}\times 6.02\times {{10}^{23}}\]\[=6.02\times {{10}^{23}}\]
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