A) 22.4 L
B) 2.24 L
C) 0.224 L
D) 0.1 L
Correct Answer: B
Solution :
44g \[C{{O}_{2}}\] occupies 22.4L at STP 4.4g \[C{{O}_{2}}\] occupies \[=\frac{22.4}{44}\times 4.4\]= 2.24L.You need to login to perform this action.
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