A) \[{{90}^{o}}\]
B) \[{{91}^{o}}\]
C) \[{{92}^{o}}\]
D) \[{{93}^{o}}\]
Correct Answer: A
Solution :
In \[\Delta \,CED,\] \[CE=ED\] \[\therefore \] \[\angle EDC=\angle ECD\] [Angles opposite to equal sides are equal] \[\Rightarrow \] \[\angle ECD={{28}^{o}}\] Also, \[\angle ECD=\angle BCA\](Vertically opposite angles) \[\Rightarrow \] \[\angle BCA={{28}^{o}}\] In \[\Delta \,BCA,\] \[y={{62}^{o}}+{{28}^{o}}\] [Exterior angle property] \[\Rightarrow \] \[y={{90}^{o}}\]
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