A) 13.11 gm/cc
B) 26.22 gm/cc
C) 52.11 gm/cc
D) None of these
Correct Answer: A
Solution :
\[\rho ={{\rho }_{0}}(1-\gamma .\Delta \theta )=13.6[1-0.18\times {{10}^{-3}}(473-273)]\] \[=13.6[1-0.036]=13.11\,gm/cc\].
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