A) 0.000558 per°C
B) 0.00057 per°C
C) 0.00027 per°C
D) 0.00066 per°C
Correct Answer: B
Solution :
As we know \[{{\gamma }_{\text{real}}}={{\gamma }_{\text{app}\text{.}}}+{{\gamma }_{\text{vessel}}}\] Þ \[{{\gamma }_{\text{app}\text{.}}}={{\gamma }_{\text{glycerine}}}-{{\gamma }_{\text{glass}}}\] \[=0.000597-0.000027=0.00057/{}^\circ C\]
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