A) 0.0015/°C
B) 0.0045/°C
C) 0.0025/°C
D) 0.0033/°C
Correct Answer: D
Solution :
\[\frac{{{V}_{1}}}{{{V}_{2}}}=\frac{1+\gamma \,{{t}_{1}}}{1+\gamma \,{{t}_{2}}}\] Þ \[\frac{100}{125}=\frac{1+\gamma \times 20}{1+\gamma \times 100}\] Þ g = 0.0033/°CYou need to login to perform this action.
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