A) 25°C
B) 35°C
C) 45°C
D) 55°C
Correct Answer: A
Solution :
\[\alpha =\frac{\Delta L}{{{L}_{0}}\Delta \theta }=\frac{(1-0.9997)}{0.9997\times 12\times {{10}^{-6}}}=25{}^\circ C\]You need to login to perform this action.
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