A) \[\frac{{{\alpha }_{s}}}{{{\alpha }_{a}}}\]
B) \[\frac{{{\alpha }_{a}}}{{{\alpha }_{s}}}\]
C) \[\frac{{{\alpha }_{s}}}{({{\alpha }_{a}}+{{\alpha }_{s}})}\]
D) \[\frac{{{\alpha }_{a}}}{({{\alpha }_{a}}+{{\alpha }_{s}})}\]
Correct Answer: C
Solution :
Given \[\Delta {{l}_{1}}=\Delta {{l}_{2}}\] or \[{{l}_{1}}{{\alpha }_{a}}t={{l}_{2}}{{\alpha }_{s}}t\] \[\therefore \] \[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{{{\alpha }_{s}}}{{{\alpha }_{a}}}\] or \[\frac{{{l}_{1}}}{{{l}_{1}}+{{l}_{2}}}=\frac{{{\alpha }_{s}}}{{{\alpha }_{a}}+{{\alpha }_{s}}}\].You need to login to perform this action.
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