A) 2.33 ´ 10?5 /°C
B) 6.0 ´ 10?5 /°C
C) 4.0 ´ 10?5 /°C
D) 2.0 ´ 10?5 /°C
Correct Answer: D
Solution :
\[\alpha =\frac{\Delta L}{{{L}_{0}}\times \Delta \theta }=\frac{0.01}{5\times 100}=2\times {{10}^{-5}}/{}^\circ C\]You need to login to perform this action.
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