A) 11 ´ 10?6 cm longer
B) 11 ´ 10?6 cm shorter
C) 11 ´ 10?5 cm shorter
D) 11 ´ 10?5 cm longer
Correct Answer: C
Solution :
\[L={{L}_{0}}(1+\alpha \Delta \theta )\] Þ \[\frac{{{L}_{1}}}{{{L}_{2}}}=\frac{1+\alpha {{(\Delta \theta )}_{1}}}{1+\alpha {{(\Delta \theta )}_{2}}}\] Þ \[\frac{10}{{{L}_{2}}}=\frac{1+11\times {{10}^{-6}}\times 20}{1+11\times {{10}^{-6}}\times 19}\] Þ \[{{L}_{2}}=9.99989\] Þ Length is shorten by \[10-9.99989=0.00011=11\times {{10}^{-5}}\,cm\]
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