question_answer

A pendulum clock keeps correct time at 0°C. Its mean coefficient of linear expansions is \[\alpha /{}^\circ C\], then the loss in seconds per day by the clock if the temperature rises by t°C is                                                      [AFMC 1993]

A)            \[\frac{\frac{1}{2}\alpha \,t\times 864000}{1-\frac{\alpha \,t}{2}}\]              

B)            \[\frac{1}{2}\alpha \,t\times \,86400\]

C)            \[\frac{\frac{1}{2}\alpha \,t\times 86400}{{{\left( 1-\,\frac{\alpha \,t}{2} \right)}^{2}}}\]    

D)            \[\frac{\frac{1}{2}\alpha \,t\times 86400}{1+\frac{\alpha \,t}{2}}\]