Answer:
\[{{t}_{C}}=\frac{{{l}_{t}}-{{l}_{0}}}{{{l}_{100}}-{{l}_{0}}}\times {{100}^{\circ }}C=\frac{0.9-0}{10-0}\times 100=\mathbf{9}{{\mathbf{0}}^{\mathbf{o}}}\mathbf{C}.\] \[{{t}_{F}}=\frac{9}{5}{{t}_{C}}+32=\frac{9}{5}\times 90+32=\mathbf{19}{{\mathbf{4}}^{\mathbf{o}}}\mathbf{F}.\]
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