Answer:
The time period of a simple pendulum is given by \[T=2\pi \sqrt{\frac{l}{g}}\] i.e., \[T\propto \sqrt{l}.\] In winter, \[l\] decreases with the fall in temperature, so T decreases and clocks run fast. In summer \[l\]increases with the increase in temperature, so T increases and clock runs slow.
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