A) \[\frac{A}{B}\]
B) \[-\frac{A}{2B}\]
C) \[-\frac{B}{2A}\]
D) \[\frac{A}{2B}\]
Correct Answer: D
Solution :
At neutral temperature E is maximum so \[\frac{dE}{dt}=0\]Þ \[\frac{d}{dt}(At-B{{t}^{2}})=0\]Þ \[A-2Bt=0\]Þ \[t=\frac{A}{2B}\]You need to login to perform this action.
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