A) \[{{290}^{o}}C,\,\,{{580}^{o}}C\]
B) \[{{270}^{o}}C,\,\,{{580}^{o}}C\]
C) \[{{270}^{o}}C,\,\,{{500}^{o}}C\]
D) \[{{290}^{o}}C,\,\,{{540}^{o}}C\]
Correct Answer: C
Solution :
No change in neutral temperature but temperature of inversion is \[{{t}_{i}}=2{{t}_{n}}-{{t}_{c}}\]Þ \[{{t}_{i}}=2\times 270-40={{500}^{o}}C\]
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