A) \[-\frac{a}{2b}\]
B) \[+\frac{a}{2b}\]
C) \[-\frac{a}{b}\]
D) \[+\frac{a}{b}\]
Correct Answer: A
Solution :
\[E=at+b{{t}^{2}}\]at inversion temperature E will be minimum Thus \[\frac{dE}{dt}=0\] Þ \[\frac{d}{dt}[at+b{{t}^{2}}]=0\] Þ \[a+2bt=0\] Þ \[t=-\frac{a}{2b}\]
You need to login to perform this action.
You will be redirected in
3 sec
