A) a/b
B) ? a/b
C) a/2b
D) ?1/ ab
Correct Answer: B
Solution :
At neutral temperature, thermal emf will be maximum. \[\therefore \,\,\frac{de}{dt}=a+bt\] For maximum or minima, \[a+b{{t}_{n}}=0\] \[\therefore \,\,\,{{t}_{n}}=-a/b\]
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