Answer:
For a perfect gas, \[PV=nRT\] \[\therefore \] \[V=\frac{nR}{P}T\] \[\therefore \] Slope of \[V-T\]graph with \[\text{T- axis}\] \[=\frac{nR}{P}\] For a given amount of gas, slope \[\propto \frac{1}{P}\]
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