A) 1.8 bar
B) 11 bar
C) 0.8 bar
D) The same as at \[27{}^\circ C\]
Correct Answer: A
Solution :
\[{{p}_{2}}=\frac{{{p}_{1}}{{T}_{2}}}{{{T}_{1}}}=\frac{2\times 270}{300}=1.8\,\,bar\]You need to login to perform this action.
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