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Railways NTPC (Technical Ability) Thermodynamics Question Bank Thermodynamics

  • question_answer
    A heat engine working on Carnot cycle receives heat at the rate of 40 kW from a source at 1200 K and rejects it to a sink at 300 K. The heat rejected is:

    A) 30 kW              

    B) 20 kW

    C) 10 kW              

    D) 5 kW

    Correct Answer: C

    Solution :

    \[{{T}_{1}}=1200\,\,K,\] \[{{T}_{2}}=300\,\,K,\] \[{{Q}_{1}}=40\,\,KW\] \[\frac{{{Q}_{1}}}{{{T}_{1}}}=\frac{{{Q}_{2}}}{{{T}_{2}}},\] \[{{Q}_{2}}=40\times \frac{300}{1200}=10\,\,kW\]


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