\[{{Q}_{12}}\,\,=\,220\,kJ,\] \[{{Q}_{23}}=-\,25\,\,kJ,\] \[{{Q}_{34}}=-\,180\,\,kJ,\] \[{{Q}_{41}}\,\,=\,\,50\,\,kJ.\] |
The work during three of the processes is: |
A) \[-\,\,230\,kJ\]
B) 0 kJ
C) 230 kJ
D) 130 kJ
Correct Answer: B
Solution :
\[\sum Q=220-25-180+50=65\,\,kJ\] \[\sum W=15-120+60+{{W}_{4\,-\,1}}=65\,\,kJ+{{W}_{4\,-\,1}}\] According to the first law thermodynamics, \[\sum W=\sum Q\] \[65+{{W}_{4\,-\,1}}=65\] \[{{W}_{4\,-\,1}}\,\,=\,\,0\,\,kJ\]You need to login to perform this action.
You will be redirected in
3 sec