A) 66 W
B) 56 W
C) 46 W
D) 36 W
Correct Answer: D
Solution :
\[{{T}_{1}}=273+12=285\,K,\] \[{{T}_{2}}=273+2=275\,K\] \[{{Q}_{1}}=57\,\,\text{J/cycle}\,\,\text{=}\,\,\text{57}\times \,\frac{1080}{60}=1026\,\,W\] \[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}=1-\frac{275}{285}=0.035=\frac{W}{{{Q}_{1}}}\] \[W=1026\times 0.025=36\,\,W\]You need to login to perform this action.
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