A) 1 and 1 kW
B) 1 and 2 kW
C) 2 and 1 kW
D) 2 and 2 kW
Correct Answer: C
Solution :
\[{{T}_{1}}=300\,K,\] \[{{T}_{2}}=200\,K,\] \[COP=\frac{{{T}_{2}}}{{{T}_{1}}-{{T}_{2}}}=\frac{200}{300-200}=\frac{200}{100}=2\] Power consumed \[=\frac{Q}{COP}=\frac{2}{2}=1\,kW\]You need to login to perform this action.
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