A) ? 288°F
B) ? 146°F
C) ? 368°F
D) +178°F
Correct Answer: A
Solution :
\[\frac{F-32}{9}=\frac{K-273}{5}\] Þ\[\frac{F-32}{9}=\frac{95-273}{5}\] Þ\[F=-288{}^\circ F\]You need to login to perform this action.
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