JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Third Law of Motion

  • question_answer
    A body of mass 5kg is suspended by a spring balance on an inclined plane as shown in figure. The spring balance measure

    A) 50 N   

    B) 25 N

    C) 500 N

    D) 10 N

    Correct Answer: B

    Solution :

        Since downward force along the inclined plane             =\[mg\sin \theta \]\[=5\times 10\times \sin 30{}^\circ \]= \[25N\]


You need to login to perform this action.
You will be redirected in 3 sec spinner