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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Third Law of Motion

  • question_answer
    In the above ques., the height to which the lift takes the passenger is

    A)             3.6 meters          

    B)               8 meters            

    C)             1.8 meters            

    D)               36 meters            

    Correct Answer: D

    Solution :

                    Distance travelled by the lift             \[=\] Area under velocity time graph             \[=\left( \frac{1}{2}\times 2\times 3.6 \right)+\left( 8\times 3.6 \right)+\left( \frac{1}{2}\times 2\times 3.6 \right)\]= \[36m\]


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