A) 1990
B) 1992
C) 1993
D) 1995
Correct Answer: C
Solution :
Starting with 1988, we go on counting the number of odd days till the sum is divisible by 7. Years \[\to \]1988 1989 1990 1991 1992 Odd days \[\to \] 2 1 1 1 2 = 7 i.e. odd days \[\therefore \] Calendar for 1993 the same as that of 1988.
You need to login to perform this action.
You will be redirected in
3 sec
