A) 0.50
B) 0.79
C) 0.84
D) 0.95
Correct Answer: B
Solution :
Standard derivation, \[\sigma ={{1}_{2}}+{{2}_{2}}+{{3}_{2}}=3.7416\] \[{{T}_{m}}=3+8+6=17\,days\] \[{{T}_{s}}=20\,days\] Probability of waiting, \[z=\frac{{{T}_{s}}-{{T}_{m}}}{\sigma }=0.802\] For \[z\text{ }=\text{ }0.802,\] area under the normal distribution curve \[=\text{ }0.7881\text{ }=\text{ }0.79\]You need to login to perform this action.
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