A) n = 4
B) n = 3
C) n = 2
D) n = 1
Correct Answer: C
Solution :
| (c) Radius of nth orbit for any hydrogen like atom \[{{r}_{n}}={{r}_{0}}\left( \frac{{{n}^{2}}}{Z} \right)\] (\[{{r}_{0}}=\]radius of first orbit of \[{{H}_{2}}\]-atom) |
| If \[{{r}_{n}}={{r}_{0}}\] Þ \[n=\sqrt{Z}.\] For Be+++, Z = 4 Þ n = 2. |
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