A) \[0.365\mu m\]and \[0.565\mu m\]
B) \[0.818\mu m\]and \[1.89\mu m\]
C) \[1.45\mu m\]and \[4.04\mu m\]
D) \[2.27\mu m\]and \[7.43\mu m\]
Correct Answer: B
Solution :
| (b) In Paschen series \[\frac{1}{{{\lambda }_{\max }}}=R\left[ \frac{1}{{{(3)}^{2}}}-\frac{1}{{{(4)}^{2}}} \right]\] |
| Þ \[{{\lambda }_{\max }}=\frac{144}{7R}=\frac{144}{7\times 1.1\times {{10}^{7}}}=1.89\times {{10}^{-6}}m=1.89\,\mu m\] |
| Similarly \[{{\lambda }_{\min }}=\frac{9}{R}=\frac{9}{1.1\times {{10}^{7}}}=0.818\,\mu m\] |
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