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JEE Main & Advanced Physics Atomic Physics Question Bank Topic Test - Atomic Physics

  • question_answer
    The energy of a hydrogen atom in its ground state is \[-13.6\ eV\]. The energy of the level corresponding to the quantum number n = 2 (first excited state) in the hydrogen atom is

    A) - 2.72 eV

    B) - 0.85 eV

    C) - 0.54 eV

    D) - 3.4 eV

    Correct Answer: D

    Solution :

    [d] \[{{E}_{n}}=\frac{-13.6}{{{n}^{2}}}=\frac{-13.6}{4}=-3.4eV\]


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