A) Dissociation decreases
B) Dissociation increases
C) Dissociation does not change
D) None of these
Correct Answer: A
Solution :
[a] \[PC{{l}_{5}}(g)\] \[\rightleftharpoons \]\[PC{{l}_{3}}(g)+C{{l}_{2}}(g)\] |
For this reaction \[\Delta n=2-1=1\] |
Value of \[\Delta n\] is positive so the dissociation of \[PC{{l}_{5}}\] take forward by decrease in pressure & by increase in pressure the dissociation of \[PC{{l}_{5}}\] decrease. |
You need to login to perform this action.
You will be redirected in
3 sec