• # question_answer What is the effect of increasing pressure on the dissociation of $PC{{l}_{5}}$ according to the equation $PC{{l}_{5(g)}}$$\rightleftharpoons$ $PC{{l}_{3(g)}}+C{{l}_{2(g)}}-x\ cal$    A)       Dissociation decreases B) Dissociation increases C) Dissociation does not change D) None of these

 [a] $PC{{l}_{5}}(g)$ $\rightleftharpoons$$PC{{l}_{3}}(g)+C{{l}_{2}}(g)$ For this reaction $\Delta n=2-1=1$ Value of $\Delta n$ is positive so the dissociation of $PC{{l}_{5}}$ take forward by decrease in pressure & by increase in pressure the dissociation of $PC{{l}_{5}}$ decrease.