A) Period = 3rd, block = p, group = 16
B) Period = 5th, block = s, group = 1
C) Period = 3rd, block = p, group = 10
D) Period = 4th, block = d, group = 12
Correct Answer: A
Solution :
[a] By obserbing principal quantum number (n), Orbital \[(s,p,d,f)\] and equating no. of \[{{e}^{-}}\]s we are able to find the period, block and group of element in periodic table.You need to login to perform this action.
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