A) 9.98 g/equiv
B) 3.2 g/equiv
C) 5.9 g/equiv
D) 0.99 g/equiv
Correct Answer: A
Solution :
[a] Gram equivalent of metal \[=geq.\] of Zn |
\[\frac{0.468}{{{E}_{M}}}=\frac{1.532}{{{E}_{Zn}}}\] |
\[\Rightarrow \] \[\frac{0.468}{{{E}_{M}}}=\frac{1.532\times 2}{65.4}\]\[\left[ \because {{E}_{Zn}}=\frac{65.4}{2} \right]\] \[{{E}_{M}}=9.98\,g/eq\] |
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