A) \[{{C}_{1}}={{C}_{2}}\]
B) \[{{C}_{1}}>{{C}_{2}}\]
C) \[{{C}_{2}}>{{C}_{1}}\]
D) Both [a] and [c] are correct
Correct Answer: C
Solution :
[c] \[Zn|Z{{n}^{+}}({{C}_{1}})||Z{{n}^{+2}}({{C}_{2}})|Zn\] |
\[\therefore \] \[{{E}_{Cell}}=-\frac{0.0591}{2}\log \frac{{{C}_{1}}}{{{C}_{2}}}\] |
For \[\Delta G\] being negative, \[{{E}_{Cell}}\] should be positive. |
\[\therefore \] \[{{C}_{2}}>{{C}_{1}}\] |
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