A) 60
B) 90
C) 18.4
D) 0.023
Correct Answer: A
Solution :
[a] \[{{\Lambda }_{eq}}=k\times 1000/N\] |
Now, \[k=1.5/250,\] |
\[\therefore \] \[{{\Lambda }_{eq}}=(1.5/250)\times 1000/0.1=60{{\Omega }^{-1}}c{{m}^{2}}e{{q}^{-1}}\] |
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