Mass of block A is 10 kg. Coefficient of friction between the block A and surface is 0.3. What is the maximum values of M for which system remains in equilibrium \[\left( g=10m/{{s}^{2}} \right)\] |
A) 2 kg
B) 6 kg
C) 3 kg
D) 5 kg
Correct Answer: C
Solution :
Maximum friction force between block A and surface is: |
\[{{f}_{_{\max }}}=\mu mg=\left( 0.3 \right)\left( 10 \right)\left( 10 \right)=\,\,30\,N\] |
Therefore, maximum tension in the string connected with block A should be 30 N. |
Now, |
\[T'\cos \,45{}^\circ =30\] ...(1) |
\[T'sin\,45{}^\circ =Mg\] ....(2) |
From equations (1) and (2), M = 3 kg |
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