JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Topic Test - Friction

  • question_answer
    Let \[\frac{1}{2\sqrt{3}}\sec \] be the coefficient of friction between blocks of mass m and M. The pulleys are frictionless and strings are massless. Acceleration of mass m is

    A)  \[\frac{\sqrt{5}\,mg}{M+\sqrt{5}\,m\,+2\,\mu \,m}\]      

    B)  \[\frac{2\,mg}{m+5\,M\,+2\,\mu \,m}\]

    C)  \[\frac{2\sqrt{5}\,mg}{M+5\,M\,+2\,\mu \,m}\]

    D) \[\frac{5\sqrt{2}\,mg}{M+\sqrt{5}\,m\,+\sqrt{2}\,\mu \,m}\]

    Correct Answer: C

    Solution :

    From the constraint net acceleration \[m=\sqrt{{{a}^{2}}+{{\left( 2a \right)}^{2}}}\,=\sqrt{5}a\]
    \[mg=T-\mu N=2ma\]
    \[N=ma\]
                \[2T=\left( M+m \right)a\]


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