A) 3/2
B) 4/3
C) 5/3
D) 7/5
Correct Answer: C
Solution :
| [c] Below 100 K only translational degree of freedom is considered. Hence \[{{\gamma }_{mixture}}=\frac{\frac{{{\mu }_{1}}{{\gamma }_{1}}}{{{\gamma }_{1}}-1}+\frac{{{\mu }_{2}}{{\gamma }_{2}}}{{{\gamma }_{2}}-1}}{\frac{{{\mu }_{1}}}{{{\gamma }_{1}}-1}+\frac{{{\mu }_{2}}}{{{\gamma }_{2}}-1}}\] according to question, \[{{\mu }_{1}}={{\mu }_{2}}\] and \[{{\gamma }_{1}}={{\gamma }_{2}}\]\[=1+\frac{2}{3}=\frac{5}{3}\] |
| \[\Rightarrow {{\gamma }_{mix}}={{\gamma }_{1}}=\frac{5}{3}\] |
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