A) \[80\times {{10}^{-14}}\,erg\]
B) \[20\times {{10}^{-14}}\,erg\]
C) \[40\times {{10}^{-14}}\,erg\]
D) \[10\times {{10}^{-14}}\,erg\]
Correct Answer: D
Solution :
| [d] Average kinetic energy |
| \[E=\frac{3}{2}kT\] Þ \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}=\frac{(273-23)}{(273+227)}=\frac{250}{500}=\frac{1}{2}\] |
| Þ \[{{E}_{2}}=2{{E}_{1}}=2\times 5\times {{10}^{-14}}=10\times {{10}^{-14}}\,erg\] |
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