A) \[2J\text{ }mo{{l}^{1}}{{K}^{1}}\]
B) \[8.3cal\text{ }mo{{l}^{1}}{{K}^{1}}\]
C) \[4.2J\text{ }mo{{l}^{1}}{{K}^{1}}\]
D) \[2cal\text{ }mo{{l}^{1}}{{K}^{1}}\]
Correct Answer: D
Solution :
[d] \[PV=RT\] Þ \[\frac{PV}{T}=R\approx 2\frac{cal}{mol\text{-}K}.\]
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