A) \[{{C}_{v}}=3,\,{{C}_{p}}=5\]
B) \[{{C}_{V}}=4,\,{{C}_{P}}=6\]
C) \[{{C}_{v}}=3,\,{{C}_{p}}=2\]
D) \[{{C}_{V}}=3,\,{{C}_{P}}=4.2\]
Correct Answer: A
Solution :
[a] \[{{C}_{P}}-{{C}_{V}}=R=2.\frac{cal}{gm\text{-}mol\text{-}K}\] which is correct for option [a] and [b]. Further the ratio \[\frac{{{C}_{P}}}{{{C}_{V}}}(=\gamma )\] should equal to some standard value corresponding to that of either, mono, di, or triatomic gases. From this point of view option [a] is correct because \[{{\left( \frac{{{C}_{P}}}{{{C}_{V}}} \right)}_{mono}}=\frac{5}{3}\]
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