A) \[\frac{g{{t}_{1}}{{t}_{2}}}{{{t}_{1}}-{{t}_{2}}}\]
B) \[\frac{g{{t}_{1}}{{t}_{2}}}{{{t}_{1}}+{{t}_{2}}}\]
C) \[\frac{2g{{t}_{1}}{{t}_{2}}}{{{t}_{1}}-{{t}_{2}}}\]
D) \[\frac{2g{{t}_{1}}{{t}_{2}}}{{{t}_{1}}+{{t}_{2}}}\]
Correct Answer: B
Solution :
[b] \[{{t}_{1}}=\frac{2u}{g+a}\] and \[{{t}_{2}}=\frac{2u}{g-a}\] Solving, \[u=\frac{g{{t}_{1}}{{t}_{2}}}{{{t}_{1}}+{{t}_{2}}}\]You need to login to perform this action.
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