A) 2 : 1
B) 4 : 1
C) 4 : 3
D) 8 : 3
Correct Answer: D
Solution :
[d] FBD of man of mass(m) FBD of man of mass (m/2)\[{{T}_{1}}=mg+mg\] | \[{{T}_{2}}=\frac{m}{2}g+\frac{m}{2}.\frac{g}{2}\] | |
\[{{T}_{1}}=2mg\] | \[{{T}_{2}}=\frac{mg}{2}\left[ \frac{3}{2} \right]=\frac{3mg}{4}\] |
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