A) 120 m
B) 75 m
C) 200 m
D) 45 m
Correct Answer: B
Solution :
[b] \[u=40\,m/s,\,g=10\,m/{{s}^{2}}\] Let t be time taken by the first ball to reach the highest point. \[V=u-gt\] \[O=40-10t\] \[t=4s\] After reaching the first ball at the highest point now both the balls will collide after 1 sec as both the balls cover equal distances in opposite directions during 1 sec. Therefore, the height of collision point = height gained by the second ball in 3 sec \[=40(3)-\frac{1}{2}(10){{(3)}^{2}}\] \[=120-45\] \[=75\,m\]You need to login to perform this action.
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