A) \[\frac{2{{E}_{1}}}{{{N}_{0}}},\frac{2({{E}_{1}}-{{E}_{2}})}{{{N}_{0}}}\]
B) \[\frac{2{{E}_{1}}}{{{N}_{0}}},\frac{2{{E}_{2}}}{{{N}_{0}}}\]
C) \[\frac{({{E}_{1}}-{{E}_{2}})}{{{N}_{0}}},\frac{2{{E}_{2}}}{{{N}_{0}}}\]
D) None is correct
Correct Answer: B
Solution :
[b] \[X(g)\xrightarrow[{}]{{}}{{X}^{+}}(g)+{{e}^{-}}\] |
If I is ionisation energy, then |
\[\therefore \] \[\frac{{{N}_{0}}}{2}(I)={{E}_{1}}\] \[\therefore \] \[I=\frac{2{{E}_{1}}}{{{N}_{0}}}\] |
If E is electron affinity, then |
\[X(g)+{{e}^{-}}\xrightarrow[{}]{{}}{{X}^{-}}(g)\] |
\[\frac{{{N}_{0}}}{2}(E)={{E}_{2}}\] |
\[\therefore \] \[E=\frac{2{{E}_{2}}}{{{N}_{0}}}\] |
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